8[c+3c+(5+c)]=1000

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Solution for 8[c+3c+(5+c)]=1000 equation:


Simplifying
8[c + 3c + (5 + c)] = 1000

Remove parenthesis around (5 + c)
8[c + 3c + 5 + c] = 1000

Reorder the terms:
8[5 + c + 3c + c] = 1000

Combine like terms: c + 3c = 4c
8[5 + 4c + c] = 1000

Combine like terms: 4c + c = 5c
8[5 + 5c] = 1000
[5 * 8 + 5c * 8] = 1000
[40 + 40c] = 1000

Solving
40 + 40c = 1000

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-40' to each side of the equation.
40 + -40 + 40c = 1000 + -40

Combine like terms: 40 + -40 = 0
0 + 40c = 1000 + -40
40c = 1000 + -40

Combine like terms: 1000 + -40 = 960
40c = 960

Divide each side by '40'.
c = 24

Simplifying
c = 24

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